A ball of mass 100 g moving with velocity of 10 m/s is stooped by a boy in 0.2 seconds. Calculate the force applied by the boy.

Answers (1)

Force F=ma

a=(v-u)/t

v=0

retardation a=-10/0.2=-50m/s2

force = ma=0.1 * (-50)=-5N 

The negative sign indicates that the force is applied against the motion

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