# A battery of 9 V is connected in series with resistors of 0.2 ?, 0.3 ?, 0.4 ? , 0.5 ? and 12 ?, respectively. How much current would flow through the 12 ? resistor?

$\\ \text{ Given, potential difference,} V =9 V \\ Resistance of resistors which are connected in series =0.2 \Omega, 0.3 \Omega, 0.4 \Omega, 0.5 \Omega and 12 \Omega respectively Current through resistor having resistance equal to 12 \Omega=? \\ Total effective resistance, R=0.2 \Omega+0.3 \Omega+0.4 \Omega+0.5 \Omega+12 \Omega=13.4 \Omega \\ We know; I=\frac{V}{R} \\ =9 V \div 13.4 \Omega=0.671 A \\ Since, there is no division of electric current, in the circuit if resistors are connected in series, thus, resistance through the resistor having resistance equal to \\ 12 \Omega=0.671 A$

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