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  • A body of mass 5 kg is acted upon by two perpendicular forces 8 N and 6 N. Give the magnitude and direction of the acceleration of the body.

A body of mass 5 kg is acted upon by two perpendicular forces 8 N and 6 N. Give the magnitude and direction of the acceleration of the body.

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The magnitude of the resulting force can be found by :

                                           R = sqrtF_1^2 + F_2^2

or                                               = sqrt8^2 + 6^2

or                                              = 10 N

Now force direction,

                                          an Theta = frac68

or                                              Theta = 37^circ

The acceleration of the body is given by :

                                                a = fracFm

or                                             a = frac105 = 2 m/s^2

Hence acceleration of the body is    2 m/s^2   and its direction is the same as of the resultant force.

Posted by

Deependra Verma

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