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A body of mass 5 kg is acted upon by two perpendicular forces 8 N and 6 N. Give the magnitude and direction of the acceleration of the body.

Answers (1)

D Deependra Verma

The magnitude of the resulting force can be found by :

$R = sqrtF_1^2 + F_2^2$

or $= sqrt8^2 + 6^2$

or $= 10 N$

Now force direction,

$an Theta = frac68$

or $Theta = 37^circ$

The acceleration of the body is given by :

$a = fracFm$

or $a = frac105 = 2 m/s^2$

Hence acceleration of the body is and its direction is the same as of the resultant force.

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