a bus travelling at a speed of 54km/h is brought to rest in 90 seconds find acceleration and distance travelled by car before coming to rest?

Answers (1)

Here a is negative (retardation)

initial velocity = 15 m/s

final velocity=0 (rest)

\\v=u+at\\0=15-a\times90\\a=\frac{1}{6}m/s^2

The distance travelled

\\v^2-u^2=-2as\\

s=\frac{u^2}{2a}=225\times3=675m

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