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a bus travelling at a speed of 54km/h is brought to rest in 90 seconds find acceleration and distance travelled by car before coming to rest?

Answers (1)

S Safeer PP

Here a is negative (retardation)

initial velocity = 15 m/s

final velocity=0 (rest)

$\\v=u+at\\0=15-a\times90\\a=\frac{1}{6}m/s^2$

The distance travelled

$\\v^2-u^2=-2as\\$

$s=\frac{u^2}{2a}=225\times3=675m$

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