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(a+b)x-26y=5a+2b+1 and 3x-y=14 find a and b for infinitely many solutions

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$For; two; given; equation; if; the; ratio; of; their; coefficient; are; equal; then; they; have; infinite; number ; of; solutions.\* Given; equations; -\* (a+b)x-26y=5a+2b+1\* 3x-y=14\* so,; the; ratio; is; -\* fraca+b3 = frac-26-1 = frac5a+2b+1-14\* now,; we; will; have; two; equations; in; two; variables; a; and; b\* using; frist; two; ratio;we; get; below; equation\* a+b=26 imes 3=78; ......eq.(1)\* using; last ; two; ratio; we; get; below; euqation\* 5a+2b+1=26 imes 14=364\* 5a+2b=364-1=363; .......eq.(2)\* now,; multiply; eq.(1); by; 2; and ; subtract; eq.(2); from; eq.(1)\* On; solving; this; we; will; get; values; of; a; and; b\* Hence,; the; solution; is; a=69; and; b=9$ $For; two; given; equation; if; the; ratio; of; their; coefficient; are; equal; then; they; have; infinite; number ; of; solutions.\* Given; equations; -\* (a+b)x-26y=5a+2b+1\* 3x-y=14\* so,; the; ratio; is; -\* fraca+b3 = frac-26-1 = frac5a+2b+1-14\* now,; we; will; have; two; equations; in; two; variables; a; and; b\* a+b=26 imes 3=78\* 5a+2b+1=26 imes 14=364\* 5a+2b=364-1=363\* now,; multiply; a+b=78,; by; 2; and subtract; them\* On; solving; this; we; will; get; values; of; a; and; b\* Hence,; the; solution; is; a=69; and; b=9$

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Deependra Verma

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