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A car moving along a straight highway with speed of 126 km h-1 is brought to a stop within a distance of 200 m. What is the retardation of the car (assumed uniform), and how long does it take for the car to stop?

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eginarrayl 	ext  Answer: Given  v_0=126 km h ^-1=126 	imes frac518=35 ms ^-1\ 	ext  Distance  X =200 m , v =0, t =? 	ext  and  a =?\ v^2=v_0^2+2 a X\ 	ext  Or,  0=v_0^2+2 a X\ 	ext  Or,  X=-fracv_0^22 a\ 	ext  Or,  200=-frac35^22 a\ 	ext  Or,  a=-frac12252 	imes 200=-3.06 m s ^-2\ 	ext  Now, time can be calculated as follows: \ v=v_0+a t\ 	ext  Or,  0=35-3.06 t\ 	ext  Or,  t=frac353.06=11.4 s endarray

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Deependra Verma

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