a car travelling at a speed of 54km/h is brought to rest in 90 seconds .Find accelaration and distance travelled before coming to rest ?

Answers (1)
S safeer

The speed of the car = 54 Km/h = 15 m/sec

given u=15m/s

v=0 (rest) 

v=u+at

The acceleration

a=-u/t=-15/90 =-1/6 m/s2

or retardation = 1/6 m/s2

 

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