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  • A charge particle after being accelerated through a potential difference ‘V’ enters in a uniform magnetic field and moves in a circle of radius r. If V is doubled, the radius of the circle will become Option: 1 <img

A charge particle after being accelerated through a potential difference ‘V’ enters in a uniform magnetic field and moves in a circle of radius r. If V is doubled, the radius of the circle will become
Option: 1 2r
Option: 2 \sqrt{2}r
Option: 3 4r
Option: 4 \frac{r}{\sqrt{2}}

Answers (1)

Here m, q and B remains the same. Therefore

\\r\propto\sqrt{V}\\r'\propto\sqrt{2V}\\\frac{r}{r'}=\frac{1}{\sqrt{2}}\\r'=\sqrt{2}r

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Safeer PP

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