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A convex lens forms an image 16 cm long of an object 4 cm long kept at a distance 6 cm from the lens. The object and the image are kept on the same side of lens. (a) What is the nature of image? (b) Find: (i) the position of image, and (ii) the focal length of the lens.

Answers (1)

\begin{aligned} &\mathrm{h_i}=16 \mathrm{cm}\\ &h_o=4 \mathrm{cm}\\ &u=-6 \mathrm{cm}\\ &f=?\\ &\begin{array}{l} m=h_i/ h_o=v / u \\ \Rightarrow 16 / 4=v /-6 \\ \Rightarrow v=-24\ cm \end{array} \end{aligned}

so image is virtual, erect and enlarged

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shubham.krishnan

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