A cylindrical conductor of length l and uniform area of cross section A has resistance R. Another conductor of length 2l and resistance R of the same material has area of cross section

Answers (1)

The resistivity of 1st conductor

p=fracRA_1l

Resistivity of 2nd conductor should be the same as they are made of same material

Let area of 2nd conductor = A1

                        p=fracRA_12l

Now,

p=fracRAl=fracRA_12l

Which gives,

A1=2A

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