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A die is thrown once then what is the probability of getting a composite number?

Answers (1)

Number of total outcomes n(T) = 6

Composite numbers = {4,6} 
Number of favourable outcomes n(E)= 2
 P(Getting composite numbers )=n(E)/n(T)
                                                  =2/6
                                                  =1/3

Posted by

Ravindra Pindel

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