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  • A die is thrown twice. Find the probability that     (i)    5 will come up at least once.     (ii)   5 will not come up either time.  

A die is thrown twice. Find the probability that

    (i)    5 will come up at least once.

    (ii)   5 will not come up either time.

 

 
 
 
 
 

Answers (1)

(i) 5 will come up at least once    \Rightarrow

    A die is thrown twice

So, total no. of outcomes = 36

Total no. of outcomes where 5 comes up at least once = 11

So, the probability that 5 will come up at least once = \frac{\text{total outcomes where 5 will come up}}{\text{Total No. of outcomes}} = \frac{11}{36}

(ii)    Total no. of outcomes = 36

        Total no. of outcomes where 5 will not come up = 36-11

                                                                                               = 25

The probability that 5 will not come up either time = \frac{25}{36}

Posted by

Safeer PP

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