A metal ‘M’ is stored under kerosene. It vigorously catches fire, if a small piece of this metal is kept open in air. Dissolution of this metal in water releases great amount of energy and the metal catches fire. The solution so formed turns red litmus blue.
(a) Name the metal ‘M’.
(b) Write formula of the compound formed when this metal is exposed to

(c) Why is metal ‘M’ stored under kerosene ?
(d) If oxide of this metal is treated with hydrochloric acid, what would be the products ?
(e) Write balanced equations for :
(i) Reaction of ‘M’ with air.
(ii) Reaction of ‘M’ with water.
(iii) Reaction of metal oxide with hydrochloric acid.

 

 

 

 
 
 
 
 

Answers (1)
S safeer

(a) Metal is Sodium 
(b) Na2O

(c) It is stored under kerosene because it catches fire, if kept in open.
(d) Products would be NaCl and H2O

(e) 
(i) Reaction of ‘M’ with air

4M+O2 -----> 2M2O
(ii) Reaction of ‘M’ with water

2M+2H2O -----> 4MOH + H2 + Heat energy 
(iii) Reaction of metal oxide with hydrochloric acid

M2O+ 2HCl -----> 2MCl + H2O

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