A pebble of mass 0.05 kg is thrown vertically upwards. Give the direction and magnitude of the net force on the pebble a. During its upward motion b. During its downward motion c. At the highest point where it is momentarily at rest. Do your answers change if the pebble was thrown at an angle with 45° with the horizontal direction? Ignore air resistance

Answers (1)

Whether the pebble is moving upward or downward, the only force acting on it is due to gravitational acceleration which always acts towards down.

F = m × a

= 0.05 × 10 = 0.5 N

When the pebble is thrown at 45° angle there are two components of force, i.e. horizontal and vertical components. But in all these cases the net effect of horizontal component will be zero.

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