A pole 5m high is fixed on the of a tower.the angle of elevation of the top of pole observed from a point A on the ground is 60degree and the angle of depression of the point A from the top of the is 45degree.findthe height of the tower.(take root3=1.732)

Answers (1)

Let the height of the tower be h 

so  \angle{BAD}=90-45=45

the distance of the point A from the foot of tower be b

so so tan 45 = \frac{h}{b}

⇒ b = x   {tan 45° = 1}

for ΔABC  \angle{BAC}=60

so tan 60° = \frac{x+5}{x}

⇒ √3x = x + 5 

⇒ 0.732x = 5

⇒ x ≈ 6.83 m 

 

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