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  • A rectangular floor which measures 15 m*8 m is to be laid with tiles measuring 50 cm * 25 cm . Find the no. of tiles required. Further if a carpet is laid on the floor so that a space of 1 m exist between its edges and the edges of the floor , What fracti

A rectangular floor which measures 15 m*8 m is to be laid with tiles measuring 50 cm * 25 cm . Find the no. of tiles required. Further if a carpet is laid on the floor so that a space of 1 m exist between its edges and the edges of the floor , What fraction of the floor is uncovered?

Answers (1)

Area of the floor = 15x8 = 120 m2

Area of the tile= 0.50x0.25 = 0.125 m2

No of tiles used = Area of floor/Area of each tile = 120/0.125 = 50*25=960 tiles

Now length of the carpet = 15-2 = 13 m

width of the carpet = 8-2 = 6 m

Area of the carpet = 13x6 = 78

Uncovered area = 120 - 78 = 42 m2

Fraction of uncoverd area = 42/120 = 0.35

Posted by

Ravindra Pindel

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