A rectangular water reservoir is 10.8 m by 3.75 m at the base . water flows into it at the rate of 18 m per second through a pipe having the cross section 7.5cm *4.5cm . find the height to which the water will rise in the reservoir in 30 minutes .

Answers (1)

Solution : Water that flows into the reservoir in one second forms a cuboid of dimensions 7.5cm 	imes 4.5cm 	imes 1800cm.

	herefore  Volume of water that flows in one second                                                                                                                                             

= (18	imes 0.075	imes 0.045)m^3 = 18	imes frac751000	imes frac451000m^3=frac2434000m^3

       Volume of the water that flows in 30 minutes   =       frac2434000	imes 60	imes 30 m^3= frac218720m^3

       Area of the base of the reservoir = (10.8 	imes 3.75)m^2

	herefore  Height of water  = volume / Area of the base       =frac218720 	imes frac110.8	imes 3.75m =2.7m 

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