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A room is 4.8m*4.2m*3.6m high determine graphically the distance between a top corner and the bottom diagonally opposite to it.

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$ Dimension of the room $ = 4.8m \times 4.2m \times 3.6m \\ $ Distance between a top corner and the bottom diagonally opposite to it is $ \\ =\sqrt{(4.8)^2 + (4.2)^2 + (3.6)^2} \\ =\sqrt{(4.8)^2 + (4.2)^2 + (3.6)^2} \\ = 7.323 $ meter

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Ravindra Pindel

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