A solid cube is cut into two cuboid of equal volumes . find the ratio of the total surface area of the given cube and that of one of the cuboids.

Answers (1)

Solution :  Let the edge of the solide cube be a units. Since the cube is cut into two cuboids of equql volumes . 

               Therefore , the dimensions of each of the cuboid are  length  = a units , breadth  = a units and  height = a/2 units . 

 Now ,      S = Total surface area of cube =6a^2 sq. units

                S_1 = Total surface area of one cuboid = 2left ( a 	imes a +a 	imes fraca2  +fraca2 	imes a
ight )=4a^2sq.units

	herefore           Required ratio = S:S_1=6a^2:4a^2=3:2

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