A sonar device on a submarine sends out a signal and receives an echo 5 s later. if the speed of sound in water is 1450 ms-1.then what is the distance of the object from the submarine

Answers (1)

Time (t) taken to hear the echo = 5 s

Distance (d) of object from submarine = d 

Total distance travelled by SONAR during reception and transmission in water = 2d

Velocity (v) of sound in water=v = 2d/t  

So

d=\frac{v*t}{2}=\frac{1450*5}{2}=3625 \ m

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