# A train 108 m long moving at a speed of 50 km/hr crosses a train 112 m long coming from opposite direction in 6 seconds. The speed of the second train is:

$\\ \text{Let the speed of the second train be x km/hr}\\ Relative speed =(x+50) \mathrm{km} / \mathrm{hr} =\left[(x+50) \times \frac{5}{18}\right] \mathrm{m} / \mathrm{sec} =\frac{250+5 x}{18} \mathrm{m} / \mathrm{sec} \\ Distance covered =(108+112)=220 m \\ \therefore \frac{220}{\frac{250+5 x}{18}}=6 \Rightarrow 250+5 x=660 \Rightarrow x=82 \mathrm{km} / \mathrm{hr}$

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