# ABC is an equilateral triangle in which the vertices of A is(3,2), B is (5,-6) . find the vertices of Câ€‹

The ordinates of both B & C are 0.

So, BC= (abscissa of B−abscissa of C)=(5−1)=4units=a

The side of equilateral ΔABC.

Now, ΔABC is equilateral and BC is on the x-axis.

So, the abscissa of A will be the mid point of BC.

The ordinate of A will be the height of ΔABC from the mid point of BC.

∴ The coordinates of A are (3,23)

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