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Opposite angles of a parallelogram are equal
<A=<C =108 and let <B=<D=a
We know that sum of the interior angles of a quadrilateral is 360. That is
2 x 108 + 2a=360
2a=360-2 x 108
2a= 360=216
2a=144
a=72
So B=D=72 and C=108