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  • ABCD is a trapezium in which ab is parallel to cd ab is equal to 20 cm bc is equal to 10 cm cd is equal to 10 cm and ad is equal to 10 cm find angle ADC.

ABCD is a trapezium in which ab is parallel to cd ab is equal to 20 cm bc is equal to 10 cm cd is equal to 10 cm and ad is equal to 10 cm find angle ADC.

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AB=20,;CD=10,;AD=BC=10,;\*ABparallel CD,;now;we;have;drawn;DE perp ;to;AB;and;similarly;CFperp AB.\*ecause riangle ADE ;and; riangle BCF;are;similar Rightarrow x=y\* AE=x=FB=y=frac20-102=5 Rightarrow x=y=5\* Now,;In; riangle ADE,\* sin heta =frac510=frac12\* We;know;that;sin 30^circ=frac12\* So,; heta = 30^circ\* angle ADC=angle ADE +angle EDC=30^circ+90^circ=120^circ\* Hence,;angle ADC=120^circ

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Deependra Verma

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