ABCDE is a regular pentagon. Calculate the magnitude of each angle of ?BED.

Answers (1)

Given n=5


	herefore Each interior angle =frac(2n-4)	imes90^circn=frac(2	imes5-4)	imes90^circ5=108^circ

In ? ABE , ∠A=108^circ and AB=AE
Rightarrow angle ABE=angle AEB =frac180^circ-108^circ2=36^circ
	herefore angle BED =angle AED-angle AEB=108^circ-36^circ=72^circ
Similarly, angle BDE=72^circ
and, angle EBD=180^circ-(72+72)^circ=36^circ

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