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An iron ball falls from a height of 1 km of the ground. If all the energy is converted into heat, the rise in temperature of the ball will be (sp. heat of iron=0.1)

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ms\Delta T=mgh

S=Specific heat of iron(s) = 0.1 kcal/kg C = 0.42 kJ/kg C 

1\times0.42\times\Delta T kilo\ joule=1\times9.8\times1\ kilo\ joule

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Safeer PP

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