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  • An object 6 cm in size is placed at 50 cm in front of a convex lens of focal length 30 cm. At what distance from the lens should a screen be placed in order to obtain a sharp image of the object ? Find the nature and size of the image. Also draw labell

An object 6 cm in size is placed at 50 cm in front of a convex lens of focal length 30 cm. At what distance from the lens should a screen be placed in order to obtain a sharp image of the object ? Find the nature and size of the image. Also draw labelled ray diagram to show the image formation in this case. 

 

 

 

 
 
 
 
 

Answers (1)

Given,

f = 30cm

u = - 50 cm

h = -6cm

Lens formula

\frac{1}{f}=\frac{1}{v}-\frac{1}{u}

\frac{1}{v}=\frac{1}{f}+\frac{1}{u}

\frac{1}{v}=\frac{1}{30}-\frac{1}{50}

v = +75cm

m = \frac{v}{u}=\frac{h_{1}}{h}

\frac{75}{-50}=\frac{h_{1}}{6}

h_{1 }=-9cm

Image formed is real, increased and enlarged.

 

Posted by

Sumit Saini

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