An object is placed at a distance of 10 cm from a convex mirror of focal length 15 cm. Find the position and nature of the image.

Answers (1)

Object distance, u = -10 cm

Focal length, f = 15 cm

Let the image distance be v

As per the mirror formula

\frac1f=frac1v+frac1u\ frac115=frac1v+frac1-10\ v=6 cm

 

m=frac-6 cm -10 cm =frac35 cm =0.6 cm

The image formed is virtual, erect, diminished and is formed 6 cm behind of the mirror.

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