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Answer it. Sin 1 degree is greater or sin 1

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$2\pi \ radian=360^0\\ \\ 1 \ radian =(\frac{360 }{2\pi} )^0=(57.3)^0$

and $Sin(1)=Sin(1 \ radian)$

So

$Sin(57.3^0) > Sin (1^0)\\ Sin(1 radian) >Sin (1^0)$

So Sin 1 is greater than Sin 1 degree

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avinash.dongre

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