Get Answers to all your Questions

header-bg qa

B) sin 62º – cos 28°trigonommetry​

Answers (1)

= sin 62º – cos 28°

= sin (90-28)º – cos 28°    { because sin (90-x)º = cos xº }

= cos 28º – cos 28°

= 0

Posted by

Ravindra Pindel

View full answer