# Bala has a stride 75 cm. If he travels by walking 5 steps forward and one step back, what is the least number of steps he needs to reach a spot 24 metres away?

$stride\;of\;man=75\;cm\\* he\;goes\;5\;step\;ahead\;and\;1\;step\;backward\\*So,\;to\;travel\;24\;m\;or\;2400\;cm\\*\Rightarrow total\;step\;required\;to\;cover\;24\;m\\* Let\;x\;be\;tha\;common\;factor\;of\;backward\;and;forward\;steps\\* 2400\;cm=75\times (5x)-75\times (1x)\\* \Rightarrow x=8\\*So,\;Forward\;step=5\times x=5\times 8=40\\* Backward\;step=1\times 8=1\times8=8\\*So,\;total\;number\;of\;steps=40+8=48\;step$

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