Assume the bus x kg sugar at the original price $ y per kg.
ATq
xy = 56
x = 56/y
( x+1)(y-1) = 56
(56/y +1)(y-1) = 56
(56+y)(y-1) = 56 y
56 y + y2 - 56 -y = 56y
y2 -y - 56 = 0
y2 -8y +7y - 56 = 0
y(y-8) + 7(y-8)= 0
(y-8)(y+7) =0
y = -7 (not possible )
Hence the original price of the sugar is y = $ 8 per kg