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(C) Find out Median from the following seriesSizeFrequency 0-10 02 10-20 18 20-30 30 30–40 45 40–50 35 50-60 30 60-70 06 70-80 03?

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Data Range Frequency Cumulative Frequency
0-10 02 02
10-20 18 20
20-30 30 50
30-40 45 95
40-50 35 130
50-60 30 160
60-70 06 166
70-80 03 169
Total 169  

 

First, add the total number of frequencies.

Here, F=169

fracF2=frac1692=84.5

Hence, the value 84.5 lies in the class interval 30-40 from the cumulative frequency table.

So, 30-40 is the median class.

Posted by

Deependra Verma

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