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Calculate the total cost of running the following electrical devices in the month of September, if the rate of 1 unit of electricity is Rs. 6.00.
    (i)    Electric heater of 1000 W for 5 hours daily.
    (ii)   Electric refrigerator of 400 W for 10 hours daily.

 

 

 

 
 
 
 
 

Answers (1)

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(i)  

  \\P_1 = 1000W = 1kW\\ t_1 = 5h

(ii)

   \\P_2 = 400W = 0.4kW\\ t_2 = 10h

No. of days in in September, n - 30

    \\E_1 = P_1\times t_1\times n\\E_1 = 1kW\times 5h\times 30 = 150kWh

    \\E_2 = P_2\times t_2\times n\\E_2 = 0.4kW\times 10h\times 30 = 120kWh

Total energy = (150 + 120)kWh = 270kWh

Total cost = 270\times 6 = Rs. \ 1620

Posted by

Sumit Saini

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