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  • Centroid of the triangle with vertices (0,0,0), (2,3,4) and (p,q,r) is (1,2,3) then p+q+r equals   

Centroid of the triangle with vertices (0,0,0), (2,3,4) and (p,q,r) is (1,2,3) then p+q+r equals 

 

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\left(\frac{0+2+p}{3}, \frac{0+3+q}{3}, \frac{0+4+r}{3}\right)=(1,2,3)

\begin{aligned} & \frac{2+p}{3}=1 \rightarrow p=1 \\ & \frac{3+q}{3}=2 \rightarrow q=3 \\ & \frac{4+r}{3}=3 \rightarrow r=5 \end{aligned}

p+q+r=1+3+5=9

Posted by

Divya Sharma

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