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Determine the AP whose 3rd term is16and 7th term is exceeds the 5th term by 12.

Answers (1)

Given 

a+2d=16

a+6d=a+4d+12 implies 2d=12, d=6

a=16-12=4

Therefore the ap is 4, 10, 16, 22, 28, 34, 40, 46......

 

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