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  • Distance between point (1,-3) (-2,5)  

Distance between point (1,-3) and (-2,5)?

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Given - Two points be $A(1,-3)$ and $B(-2,5)$

Solution- Using formula, $AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Substitute the coordinates:  $\sqrt{(-2 - 1)^2 + (5 - (-3))^2} = \sqrt{(-3)^2 + 8^2} = \sqrt{9 + 64} = \sqrt{73}$

Therefore, the distance between the two points is $\sqrt{73} \approx 8.54$ units.

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Saniya Khatri

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