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Distance between point (-1,3) and (5,2)?

 

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Given - Two points be $A(-1, 3)$ and $B(5, 2)$

Solution- Using formula, $AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Substitute the coordinates:   $AB = \sqrt{(5 - (-1))^2 + (2 - 3)^2} = \sqrt{6^2 + (-1)^2} = \sqrt{36 + 1} = \sqrt{37}$

Therefore, the distance between the two points is $\sqrt{37} \approx 6.08$ units.

Posted by

Saniya Khatri

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