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  • Distance between point (2,5) (-4,1)  

Distance between point A = (2, 5) and point B = (-4, 1)?

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Given - Two points be $A(2,5)$ and $B(-4,1)$

Solution- Using formula, $AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Substitute the coordinates:   $AB =\sqrt{(-4 - 2)^2 + (1 - 5)^2} = \sqrt{(-6)^2 + (-4)^2} = \sqrt{36 + 16} = \sqrt{52} = 2\sqrt{13}$

Therefore, the distance between the two points is $\sqrt{52} = 2\sqrt{13} \approx 7.21$ units.

Posted by

Saniya Khatri

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