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Distance between point (4,2) and (4,-2)?

 

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Given - Two points be $A(4,2)$ and $B(4,-2)$

Solution- Using formula, $AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Substitute the coordinates:  $\sqrt{(4 - 4)^2 + (-2 - 2)^2} = \sqrt{0 + 16} = \sqrt{16} = 4$

Therefore, the distance between the two points is $4$ units.

Posted by

Saniya Khatri

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