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Estimate the frequency associated with photon of energy 2 eV.

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Given energy= 2eV

eV = hf

h = $6.63 \times 10 ^{-34}Js$ (planks constant)

$2=6.63 \times 10 ^{-34}\times f$

$f= \frac{2\times1.6\times10^{-19}}{6.63 \times 10 ^{-34}}= 4.8\times10^{14}Hz$

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