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  • Explain Solution R.D.Sharma Class 12 Chapter 3 Inverse Trigonometric Function Exercise Multiple choice questions Question 37 maths Textbook Solution.

Explain Solution R.D.Sharma Class 12 Chapter 3 Inverse Trigonometric Function Exercise Multiple choice questions Question 37 maths Textbook Solution.

Answers (1)

Answer: 0.96

Hint:2 \sin ^{-1} x=\sin ^{-1}\left(2 x \sqrt{1-x^{2}}\right)

Given: \sin \left(2\left(\sin ^{-1} 0.6\right)\right)

Solution:

            \sin \left(2\left(\sin ^{-1} 0.6\right)\right)

            2 \sin ^{-1} x=\sin ^{-1}\left(2 x \sqrt{1-x^{2}}\right)

So,      

             \sin \left(\sin ^{-1}\left(2(0.6) \sqrt{1-(0.6)^{2}}\right)\right)=\sin \left(\sin ^{-1} 0.96\right)

                                                                              =0.96

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