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Factor: 81x^6 - 25y^10

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The given expression

                                       $$ 81 x ^6 - 25 y^10 $$\$$ $$ (9x ^3)^2 - (5y^5)^2$$\$$ $$ (9x^3 + 5 y^5) (9x^3 - 5y^5)

Hence,     $$ (9x^3 + 5y^5) (9x^3 - 5y^5) $$

Posted by

Deependra Verma

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