factorize: (x-2y)^3 +(2y-3z)^3+(3z-x)^3

Answers (1)

solution: let a=x-2y ,b=2y-3z and c=3z-x. then

a+b+c=x-2y+2y-3z+3z-x=0

	herefore a^3+b^3+c^3=3abc

 	herefore (x-2y)^3+(2y-3z)^3+(3z-x)^3=3(x-2y)(2y-3z)(3z-x)

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