factorize x^3+3x^2+3x-7 .

Answers (1)

solution: we have , x^3+3x^2+3x-7

=(x^3+3x^2+3x+1)-8      [adding and subtracting1]

=(x+1)^3-2^3                       left [ a^3-b^3=(a-b)(a^2+b^2+ab) 
ight ]

=(x+1-2)(x^2+2x+1+2x+2+4)=(x-1)(x^2+4x+7)

 

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