factorize: x^3 - 3x^2+3x+7

Answers (1)

solution: we have ,

x^3-3x^2+3x+7

=(x^3-3x^2+3x-1) +8       [adding and subtracting 1]

=(x-1)^3+2^3              [a^3+b^3=(a+b)(a^2+b^2-ab)]

=(x-1+2)left  (x-1)^2-2(x-1)+4 
ight

=(x+1)(x^2-4x+7)

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