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Find all the roots of the equation 3x^2-x^2-8x-2=0

Answers (1)

3x2-x2-8x-2=0

2x2-8x-2=0

x2-4x-1=0

x2-4x-1=0

x^2 -4x -1 =0 \\\\ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \\\\ x = \frac{-(-4) \pm \sqrt{(-4)^2 - 4 \times 1 \times (-1)}}{2\times 1} \\\\ x = \frac{4 \pm \sqrt{16 - 4 \times 1 \times (-1)}}{2\times 1} \\\\ x = \frac{4 \pm \sqrt{20}}{2\times 1} \\\\ x =2 \pm \sqrt{5} \\\\

 

Posted by

Ravindra Pindel

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