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Find six arithmetic means between 3 and 17

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6 arithmetics means between 3 & 17 so total terms = 8
let common difference be d

first term, A1 = 3

8th term, A8 = 3 + 7d = 17
d = 2
A2 = 3+2 = 5
A3 = 5+2 = 7
A4 = 7+2 = 9
A5 = 9+2 = 11
A6 = 11+2 = 13
A7 = 13+2 =15

Posted by

Deependra Verma

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