Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Find the cartesian equation of the plane passing through the intersection of the planes and <img alt="2x - y + z = 1" src="https://learn.

Find the cartesian equation of the plane passing through the intersection of the planes x + 2y - 3 = 0 and 2x - y + z = 1and the origin i.e. (0, 0, 0). Also write the equation of the plane so obtained in vector form.

 

Answers (1)

Equation of plane passing through the intersection of two plane:

x + 2y - 3 +\lambda (2x - y + z - 1)= 0

x(1+2\lambda) + y(2-\lambda) +z\lambda = \lambda +3

This plane is passing through (0,0,0)

0(1+2\lambda) + 0(2-\lambda) +0\lambda = \lambda +3

\lambda=-3

Required Equation of the plane

x(1-6) + y(2+3) -3z = -3 +3

-5x + 5y -3z = 0

In vector from

\vec{r}.(-5\hat{i} + 5\hat{j} -3\hat{k}) = 0

 

Posted by

Safeer PP

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE 12th result 2025 sees more in compartment, JNVs on top, perfect-scorers in minor subjects
anam-khan

Low score in CBSE results? Courses, career options after 12th open to you
anam-khan

CBSE class 10, 12 results: West Bengal CM Mamata Banerjee congratulates successful candidates

Latest Question