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Find the coordinates of the point where the line \frac{x-1}{3}=\frac{y+4}{7}=\frac{z+4}{2} cuts the xy-plane.

 

 

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Given:

Line \frac{x-1}{3}=\frac{y+4}{7}=\frac{z+4}{2}

Line cut x-y plane => z=0\\ $ Put $\mathrm{z}=0$ \\ \\ $\frac{\mathrm{x}-1}{3}=\frac{\mathrm{y}+4}{7}=2 \\ \\$ Coordinates of points where line cuts is (7,10,0)

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Safeer PP

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